Series

Fiveconic — the series

4 essays on one idea, from the one that introduces it to the one that assumes the rest.
  1. horizon25withheldfive marks fitted, one withheldcorrect from 26 cm, at 160 mm widethe withheld mark is 2e-13 px off the fitted conic

    Five marks and the sixth

    Five points determine a conic exactly — five coefficients up to scale, five equations, nothing left over — so a fit through five marks on a photograph is not a fit at all. The sixth mark, withheld, lands on the curve to 1.9e-13 px. And the moment a sixth mark is used, the arithmetic changes character completely: it becomes a least-squares problem, and the residual starts telling you something the five could never say.

    part 3 · foundations
  2. horizonflat on the groundleaning 23.6°two circles, 6.4 m across, in planes 23.6° apartcorrect from 26 cm, at 160 mm widetwo poses, 23.6° apart, one picture

    Two circles, one picture

    A photographed circle leaves its own pose ambiguous, and not a little: two congruent circles in planes 23.6° apart draw the same conic to 1.1e-16 on normalised coefficients, both of them in front of the camera. On top of that the distance is free, so the family is two discrete poses each with one continuous parameter — and a plane one degree from either draws a conic 2.5e-4 away, which is what makes the agreement a measurement.

    part 4 · foundations
  3. fitted on five lines, tested on seven points7.4e-10 px

    Five tangents name the same conic

    Fitting a conic to five lines is the same six-coefficient nullspace problem as fitting one to five points, with the roles exchanged, and it lands on the same curve to 2.6 × 10⁻¹¹ pixels. What duality does not promise is that the two are equally good evidence — and measured at equal marking precision they are, to within seventeen per cent, because a drawn tangent is made of points.

    part 5 · foundations
  4. 123456Pascal · family at 0.500correct from 23 cm, at 160 mm widethree meets, collinear to 1.2e-12 px

    Pascal's line, and the theorem underneath Pappus

    Six points of a conic, three meets of opposite sides, collinear to 1.3e-12 px. Flatten the conic towards a pair of lines and the residual never leaves the axis — 5.7e-14 px at the end, where the theorem has become Pappus's — so Pappus is the degenerate case of Pascal reached continuously rather than a separate theorem that resembles it.

    part 6 · foundations

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